Last poster before threadlock gets a cookie (cookie thread (Part 7)) (Part 8)

Y are u dumb

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I think he thinks about Ramsey…

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OH gordon ramsey i see

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our main wifi has run out (i stole the neighbors) and my brother has been staring at screenshots of google images from these characters (kids horror mascot blegh) for a good time now i think he’s obsessed

i can sorta understand the white one but it scares me beacuse he legitimately knows what a furry is from his brainrot youtube videos

he saw the preview of this message and freaked out trying to grab my phone

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how old is he

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HAHAHAHAHA YOURE SO MEAN

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7 he’s punching me rn

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…oh no

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This is so cute :sob:

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“Oh my god guys AI will take over the world” - Elon Musker

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we see 3 triangles and a quadrilateral

but there are other triangles as well.

bottom left a 7 size triangle (4+3)
bottom right a 6 area (4+2)
top left a 3+? area triangle
top right a 2+? area triangle

(there is a ratio rule somewhere where two of the pairs should have the same ratio, but as I said, I haven’t used math theory for years.)

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as for this one, I think there is at least one crucial information missing.

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like I can give you an estimate, but without knowing how long either circles radius is, we literally can’t even start to count anyything.
(if the bigger circle’s radius is 12, than the shaded area is 12x12xpi/4 (since the little circle is literally non-existent at that point…)

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Wait, is this true for any quarter-circle (assuming R1 >= 12) ?

Radius quartercircle = X
Area quartercircle = π • X²
Radius of small circle = ½ • sqrt (X² - 12²)
Shaded area = (¼ π • X²) - π • (¼ • X² - 12²)
= ¼πX² - ¼πX² + 144π
= 144π

…there’s no way this is it, right?

If R2 is x.

Than R1 is 12+2× since the two line are parrallel to each other.

So the are of the area of quarter circle is

((12+2x)^2 * pi)/4

(4x^2+48x+144)*pi/4= (x^2+12x+38)*pi

The are of the little circle should be x^2×pi

The shaded area should be the difference between the quarter and the small circle

Which is

(x^2+12x+36) * pi - (x^2 * pi)

x^2 * pi + 12x * pi + 38 * pi - x^2 * pi

12x* pi + 36 *pi

(So it’s not true for all, only if x=0)

[This is a wrong answer, but I wrote down in the last 20 minutes, who finds my mistake?]

Because this means that as long as you replace 12 with any number, it would still function; the answer would always be [n² • π].

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@arctic can you send a vocaroo of you saying “a bo’a 'u 'uoua”

Funniest part is: I never learned what X is,
Because it ended up not being needed / being eliminated in the process.