Last poster before threadlock gets a cookie (cookie thread (Part 7)) (Part 8)

The 144 pi can’t be right.
(That’s the full big circle’s area)

The big circle’s area is X²π, and all we know is that X > 12.

Okay, you still need to divide with 4, to get the are of the quarter circle.

This chat is infested with geometry nerds! @Atlas Deploy the life rafts

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Which is what I did, but also:

do you want me to say it like that or how i would actually say it

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Hmmm can you say it how you normally would say it? :blush:

so… bottle of water, okay

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Yessss

I assume this part is simple.

Radius of small circle = Y
(2Y)² + 12² = X² // Pythagoras Theorem
Y = ½ • sqrt (X² - 12²)

Shaded area = [area quarter circle] - [area small circle]
= ¼ π X² - π • (½ • sqrt (X² - 12²))²
= ¼ π X² - π • (¼ • (X² - 12²)) // …ah, I got something wrong here.
= ¼ π X² - π • (¼ X² - ¼ • 12²)

…except I forgot to apply ¼ for the 144π.
So the actual answer is 36π.

@Marluna, you were right: I was wrong.
My method is correct, but I made a small error in my calculations.

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And my method is wrong.

(It only works on x=0, because in that case the tangent, and the big circle’s radius is the same.)

Yes.

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I suppose this one is the only one left…
Oh well. Either someone else will figure it out, or it will be forgotten in due time.

Arcyyyy did you fall asleepppp :sob:

Sleepy puppy

I want to hear you say bottle of water nowwwww

he said it

smh my head

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“Vocaroo from tutuu”

“I can hear the birds chirping in the background”

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