The 144 pi can’t be right.
(That’s the full big circle’s area)
The big circle’s area is X²π, and all we know is that X > 12.
Okay, you still need to divide with 4, to get the are of the quarter circle.
Which is what I did, but also:
do you want me to say it like that or how i would actually say it
Hmmm can you say it how you normally would say it?
so… bottle of water, okay
Yessss
I assume this part is simple.
Radius of small circle = Y
(2Y)² + 12² = X² // Pythagoras Theorem
Y = ½ • sqrt (X² - 12²)
Shaded area = [area quarter circle] - [area small circle]
= ¼ π X² - π • (½ • sqrt (X² - 12²))²
= ¼ π X² - π • (¼ • (X² - 12²)) // …ah, I got something wrong here.
= ¼ π X² - π • (¼ X² - ¼ • 12²)
…except I forgot to apply ¼ for the 144π.
So the actual answer is 36π.
@Marluna, you were right: I was wrong.
My method is correct, but I made a small error in my calculations.
And my method is wrong.
(It only works on x=0, because in that case the tangent, and the big circle’s radius is the same.)
Yes.
I suppose this one is the only one left…
Oh well. Either someone else will figure it out, or it will be forgotten in due time.
Arcyyyy did you fall asleepppp
Sleepy puppy
I want to hear you say bottle of water nowwwww
he said it
smh my head
“Vocaroo from tutuu”
“I can hear the birds chirping in the background”