I’m aware. This means that it’s one of the exclusive viable ET combinations that can’t be solved by a Chambermaid in one night.
The Barber will likely never activate and so there will be no mechanical information to bluff.
Teensy rules (5 or 6 players) are that the Minion and Demon don’t learn each other, and the Demon won’t learn bluffs.
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again, vortox makes the first not true
A masochists wet dream
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Truly this is a Mathematician
's Hell
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Evil Twin (doesn’t wake) + High Priestess (does wake).
The Chambermaid checks the Evil Twin and the Monk. Either a 0 or 2 would be valid.
The Chambermaid checks the High Priestess and the Monk. Either a 0 or 1 would be valid.
The Chambermaid checks the Evil Twin and the Mathematician. Either a 1 or 2 would be valid.
The Chambermaid checks the High Priestess and the Mathematician. Either a 0 or 2 would be valid.
Let’s say the Chambermaid checks a twin claiming HP and a player claiming Mathematician, and learns a 2. It wouldn’t confirm a Twin, but it’d confirm the Mathematician as that registers as not waking up. If the Chambermaid learns a 1 or 0, it confirms the Twin either way, or that the other player is the Vortox.
In other words, the Good Twin practically has to be the Mathematician, Chambermaid or Barber. ET-Heretic doesn’t work because the good Heretic outs immediately.
if they learn a 2 on a twinHP and player 2 then either player 2 is not waking (on n2, math heretic barber. on n1, hag vortox math heretic barber monk) or the twin is evil, which in a 5 or 6 player game is very plausible that you check someone weird
though maybe this script does need another character that doesnt wake n1, though its super plausible that a heretic would hide
basically lots of good players have reason to hide and the chambermaid info confirms probably an okay amount for an average of 2 nights of them being alive
i think if you have one player claiming to have solved the twins by f4 then thats okay in a teensy
host it in closet !!!
Just had a FOR game end with a D1 rerack from Spartacus guess earlier.
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stupid question for BotC enjoyers: let’s say you’re in a three-minion game, and one of the minions is a Marionette, but then (by sheer random chance) the Demon ends up bordered on both sides by the other two minions
what do you do? do you have to re-rand the game or are you allowed to e.g. make the Marionette a player who neighbors a Demon-neighboring minion?
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you’re supposed to remove a second Minion from the bag during setup and replace a Townsfolk with that Minion on the first night
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Assuming you’re running the game in person where it’s harder to rerand games secretly, you can use placeholder good tokens and then tell someone they’re an evil Minion instead, to ensure a legal setup.
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so does that minion just get a free bluff then?
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…Yeah, that happens.
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Off script Kazali.
either of the two in the last paragraph are probably the best solutions
afaict the official stance is “rerand” but sometimes thats just annoying without much actual benefit
either way both reranding and putting the mario as close to the demon as possible are less mechanically detrimental than subbing a minion so i support those over the others
however it is totally valid to not put the demon in the bag to avoid this problem, then give them the townsfolk token they received as a bluff
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This is also how you can avoid shit like King being the only option in a Choirboy game
It’s also the only way to legally run a Marionette Atheist
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You could put an Atheist intending to make them the Drunk, and instead making them the Marionette.
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Why does this script have all three of Atheist, Drunk and Marionette
What do you mean I’ve done this before 
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