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But the lore is what gives the movie life!
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Itās a TV show
Yes I know Jane
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Alignment: Pain to balance.
Role: Fun to balance.
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On table: 100 coins (2 sides; 1 head, 1 tail). 10 heads are facing up; 90 heads are facing down.
Goal: Without [any ability to discern the coins], separate the coins into two piles containing the same number of heads facing up, without removing them from the table.
Sub-goal: From the smallest pile, you can obtain any number of coins where the tails are facing up. You may only take these coins iff the (main) goal was reached.
Variant: 6 coins, 3 face-up heads, 3 face-up tails.
Max 3 heads. Min 0 heads.
arfff mimimimi
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this is a ted-ed riddle right
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Ye. Minus the subgoal.
Why is mita the cat emoji 
This anime women embodies this emoji so well
Woman
So we canāt see the coins, but we know, that 10 coins are facing heads up, right?
I would just pick 10 coins in the smaller pile, and switch which side their faces up.
Since I am switching the 10 coins I am putting in the smaller pile, it doesnāt matter, how many head facing coins I originally picked, the two piles will always have the same amount of coins facing heads up.
(for example, if I picking 6 heads, that means, the bigger pile has 4 heads, and the smaller pile also has 4 tails, after I switch the 10 coins, the smaller pile will have 4 heads as well. This method works for all cases from 0 to 10 heads in the smaller pile.)
In this case, I probably would switch the 90 coins of the big pile. (it is more likely I am picking more tail facing up coins in my smaller pile, if I am picking 10 coins randomly.)
Reasoning is same as above.
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This on is trickierā¦
I donāt see the solution at the moment.
No. Itās the exact same āpuzzleā with the exact same solution. The min-max thing is just how many heads/tails you can get if you were to use the same method as the original puzzle.
Smart~
I didnāt think of that before! 
