Where did you got stuck?
i said yet
80% chance I get roped in
yea fair lmao
May?
ok sure iâll host for fam5
i have so many shit ideas
real
somewhat true
false!
this was already known thbthtbthbthbthtbhb
iâm surprised he didnât mention real analysis
okay just wanting a benchmark how blinded are you guys by streetlights
Cause I donât feel myself being oldâŚ
not really
i ask because i know my eyes are weird but because theyre my Seeing Balls and always have been i have no frame of reference as to how hostile light infrastructure is to everyone else
I usually cut myself on carton boxes during work.
(somehow the especially smal boxesâ edges are super sharp, so itâs almost impossible to fold them without cutting yourself in the process.)
So basically, what I understand is...
- The vertical renban lines contain a set of [2345 + (1 or 6)] and [5678 + (4 or 9)]. The bent parts at columns 1 and 9 contain a 5 and either (4 or 6).
- Knowing the above, C2R5 and C8R5 contain (1 or 9), limiting the center thermosâ boundaries to [2âŚ8]. 1-9 pair are in C4R6 and C6R4.
- 5 has in block 5, row 5. So do 2 and 8, removing them from the lower bound to the left and upper bound to the right.
- Eliminating numbers, B5R5 has to be 2-5-8, with C5R4 being a 7, and C5R6 being a 3.
- I noticed that the renban lines at block 2 and 8 have to contain 2, 5, and 8 in each of them.
- Since 8 is in C6R5, and the 8 in block 2 and 8 has to be in a renban line of length 3 (because the renban lines of length 2 are fully inside column 6), 8 in block 8 has to be either in C5R8 or C5R9. Whichever one it is, since it is inside a renban line of length 3, it has to have a 7 in C6R9.
- Here is where I usually end up with. After this point, I got nothing and usually start brute-forcing things. To no avail, obviously.
Try to check where 5 can be in column 6 (from what I understood from your method, you shouldnât have a concrete place for them yet, but it should give you a nice restrain for the remaining solve), afterwards, where 1 can be in column 5. (Itâs a bit brute-forcey method, but it was how I ended up solving it)
Why did you eliminate the 8 from c5r7?
a bit more detailed clue for the vertical renbans
C2r4, c2r6 as well c8r4 and c8r6 see all parts of both of their respective vertical renbanâs so the canât have any of the overlapping numbers. (Essentialy eliminating 46 from those places.)
Since c2r4 canât be 4 anymore, (because the above reason) and the lower-end renban always contain 234, as well the v clue always contain either 1-4 or 2-3 you wouldnât be ever to hide any of those number in the box 1-4 renban making that renban essentially an upper-end renban.
The c1r4, c1r6, c9r4, c9r6 cells contain two 5s, and either 4s or 6s as rest, it canât be an x-wing, since if you put both number (other than the 5) as the same, you wonât be able to place that number in box5. (Since 2-5-8 already is occupying those cells, and none of those number is equal with either 4 or 6)
So 4 and 6 should occupy opposite corners in those four cells.
I did not realize double-v was pronounced as dabuhl-u
Itâs surprisingly low amount of languauges where itâs called double-v.